Practice question

**Angular SHM** of pendulum results from restoring torque τ = -m g L sinθ ≈ -m g L θ for small θ, analogous to linear SHM with ω = √(g/L). This relation allows period determination from length and local gravity, illustrating gravitational influence on oscillation. Maximum angular speed: ω = √((g/L)) = √((10/1)) = √(10) rad/s . Maximum speed: vₘₐₓ = ω A = ω (L θ) = √(10) × 1 × 0.1 ≈ 0.316 m/s . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 0.316 m/s follows, reflecting SHM