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Question

A mass of \( 2 \, \text{kg} \) on a spring with \( k = 200 \, \text{N/m} \) has \( A = 10 \, \text{cm}
\). What is the kinetic energy at \( x = 5 \, \text{cm} \)?

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Explanation

**Forced oscillations** result when external periodic driving force F = F₀ cos(ω_d t) acts on oscillator, steady-state frequency equals driving frequency ω_d, amplitude A = F₀/√((k - m ω_d²)² + (b ω_d)²) depends on proximity to natural frequency ω₀ = √(k/m). Resonance when ω_d ≈ ω₀, amplitude maximum. Total energy: E = (1/2) k A² = 0.5 × 200 × (0.1)² = 1 J . Potential energy: U = (1/2) k x² = 0.5 × 200 × (0.05)² = 0.25 J . Kinetic energy: K = E - U = 1 - 0.25 = 0.75 J . Applying x = A cos(ωt + φ), v

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