Skip to content

Question

A force F\=6i^+8j^N acts on a particle moving along d\=3i^−2j^m. What is the work done?

Options

Choose one · Correct answer highlighted

Explanation

Work W=F·d=Fd cosθ per NCERT Chapter 6. Positive if force along displacement. Using given F, d, θ, calculation gives 2 J. Work-energy theorem W=ΔK confirms. So option B is correct.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.