Practice question
Question
A force F\=6i^+8j^N acts on a particle moving along d\=3i^−2j^m. What is the work done?
Explanation
Work W=F·d=Fd cosθ per NCERT Chapter 6. Positive if force along displacement. Using given F, d, θ, calculation gives 2 J. Work-energy theorem W=ΔK confirms. So option B is correct.
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