Practice question

Given: A coil of self-inductance 0.8 H has its current decreased from 6 A to 3 A in 0.2 s. What is the magnitude of the induced emf? These values define the system as per NCERT data. Formula: varepsilon = L Δ I/Δ t. This is standard NCERT relation. Substitution & Calculation: Δ I = 3 - 6 = -3 A, Δ t = 0.2 s . varepsilon = 0.8 × -3/0.2 = 0.8 × (-15) = -12 V, magnitude = 12 V. Result: The computed value matches expected outcome and confirms correct choice as per NCERT.