Practice question

Given: A circuit has a 6 V battery with 1 Ω internal resistance and two resistors 2 Ω and 3 Ω in parallel. What is the total current? These values define the system as per NCERT data. Formula: Parallel resistance: 1/R_p = 1/2 + 1/3 = 3 + 2/6 = 5/6 Rightarrow R_p = 6/5 = 1.2 Ω. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Total resistance: R_{total = 1 + 1.2 = 2.2 Ω . Current: I = fracvarepsilonR_{total = 6/2.2 approx 2.73 A . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.