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Question

A car accelerates uniformly from 10m/s to 25m/s over 150m, then decelerates to 5m/s over the next 80m. What is the total time taken?

Options

Choose one · Correct answer highlighted

Explanation

Phase 1: v2=v02+2ax, 252=102+2a(150)⇒625=100+300a⇒a=1.75m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 12 s as the result, so option A is correct.

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