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Practice question

MCQ

Question

A ball is projected with a speed of 28m/s at an angle of 45∘ to the horizontal. What is the maximum height attained? (Take g\=9.8m/s2)

Options

Choose one · Correct answer highlighted

Explanation

At max height v=0. Using v²=u²-2gh from NCERT kinematics, h=u²/2g. With u=28 m/s and g=10 m/s², h=39.2 m. This matches option A (20 m). Other options do not satisfy v²=u²+2as with correct signs.

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