Skip to content

Question

A 3kg particle moves with velocity v\=6i^−4j^m/s at r\=2j^m. What is the z-component of its angular momentum?

Options

Choose one · Correct answer highlighted

Explanation

L = r×p = |i^j^k^0206−40| = k^(0×(−4)−2×6) = −12k^kg m2/s. Z-component = −12kg m2/s. As per NCERT, applying relevant law/formula with correct units and sign convention leads to -12 kg m²/s. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.

Discussion

Comments

0 comments

No comments yet. Be the first to start the discussion.