Practice question

Given: What is the total energy of a 100 kg satellite orbiting Earth at 3 R_E from the nter? ( M_E = 6 × 10²⁴kg, R_E = 6.4 × 10⁶m, G = 6.67 × 10⁻¹¹N m²/kg² ) Formula: E = -G M_E m/2 r. Substitution & Calculation: r = 3 R_E = 3 × 6.4 × 10⁶= 1.92 × 10⁷m . E = -frac6.67 × 10⁻¹¹ × 6 × 10²⁴ × 1002 × 1.92 × 10⁷. E = -frac4.002 × 10¹⁶³.84 × 10⁷approx -1.04 × 10⁹J . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.