Practice question
Question
What is the degree of dissociation of 0.01 M acetic acid if its molar conductivity is 39.05 S cm² molâ»Â¹ and Lambda_mâ° = 390.5 S cm² mol^{-1 ?
Explanation
Given:
What is the degree of dissociation of 0.01 M acetic acid if its molar conductivity is 39.05 S cm² molâ»Â¹ and Lambda_mâ° = 390.5 S cm² mol^{-1 ?
These values define the system as per NCERT data.
Formula:
α = Lambda_m/Lambda_mⰠ= 39.05/390.5 = 0.1 ..
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Substituting values like 1.2 × 10â»âµ, 236 J kgâ»Â¹ Kâ»Â¹, CH₃CHâ‚‚NHâ‚‚ etc. into the formula and simplifying step by step.
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
Discussion
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