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Practice question

Question

What is the degree of dissociation of 0.01 M acetic acid if its molar conductivity is 39.05 S cm² mol⁻¹ and Lambda_m⁰ = 390.5 S cm² mol^{-1 ?

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Explanation

Given: What is the degree of dissociation of 0.01 M acetic acid if its molar conductivity is 39.05 S cm² mol⁻¹ and Lambda_m⁰ = 390.5 S cm² mol^{-1 ? These values define the system as per NCERT data. Formula: α = Lambda_m/Lambda_m⁰ = 39.05/390.5 = 0.1 .. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substituting values like 1.2 × 10⁻⁵, 236 J kg⁻¹ K⁻¹, CH₃CH₂NH₂ etc. into the formula and simplifying step by step. Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.

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