Practice question
Question
What is the conductivity of a 0.02 M NaCl solution at 298 K if its molar conductivity is 115 S cm² molâ»Â¹?
Explanation
Given:
What is the conductivity of a 0.02 M NaCl solution at 298 K if its molar conductivity is 115 S cm² molâ»Â¹?
These values define the system as per NCERT data.
Formula:
Lambda_m = kappa/c × 1000, kappa = Lambda_m × c/1000.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
kappa = 115 × 0.02/1000 = 0.0023 S cm^{-1 = 2.3 × 10â»Â³ S cm^{-1 .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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