Practice question
Question
Two parallel wires 0.02 m apart carry 10 A and 3 A in the same direction. What is the force per unit length? ( μ_0 = 4 Ï€ × 10â»â· T m/A )
Explanation
Given:
Two parallel wires 0.02 m apart carry 10 A and 3 A in the same direction. What is the force per unit length? ( μ_0 = 4 Ï€ × 10â»â· T m/A )
These values define the system as per NCERT data.
Formula:
f = μ_0 I_1 I_2/2 π d.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
f = frac4 Ï€ × 10â»â· × 10 × 32 Ï€ × 0.02 = frac120 × 10â»â·â°.04 = 3 × 10â»âµ N/m .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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