Practice question

Given: The K_p for NH₃(g) <=> 1/2 N₂(g) + 3/2 H₂(g) is 0.2 atm at 500 K. What is K_c if R = 0.0821 L · atm · mol^{-1 · K^{-1 ? Formula: Δ n = (1/2 + 3/2) - 1 = 1, K_p = K_c (RT)^{Δ n. Substitution & Calculation: RT = 0.0821 × 500 = 41.05, 0.2 = K_c · 41.05, K_c = 0.2 / 41.05 approx 0.00487 . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.