Practice question
Question
The solubility product of Bi₂S₃ is 1.0 × 10⁻⁹⁷. What is its solubility in water?
Explanation
Given:
The solubility product of Bi₂S₃ is 1.0 × 10⁻⁹⁷. What is its solubility in water?
Formula:
Bi₂S₃(s) <=> 2Bi³+ + 3S²-, K_{sp = (2S)² · (3S)³ = 108S⁵.
Substitution & Calculation:
108S⁵ = 1.0 × 10⁻⁹⁷, S⁵ = 9.26 × 10⁻¹⁰⁰, S approx 1.32 × 10⁻²⁰M.
Final Result:
The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.
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