Practice question
Question
How much heat is required to raise the temperature of 2kg of water from 20∘C to 50∘C? (Specific heat capacity of water = 4186J kg−1K−1)
Explanation
Given: m = 2kg, ΔT = 50−20 = 30∘C, s = 4186Jkg−1K−1. Heat required: ΔQ = msΔT = 2×4186×30 = 251160J. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 251.16 kJ. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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