Practice question

Given: A wave on a string has an amplitude of 2 cm and a wavelength of 0.5 m. What is the maximum transverse speed of a particle on the string if its frequency is 20 Hz? These values define the system as per NCERT data. Formula: Amplitude a = 0.02 m, frequency v = 20 Hz. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Angular frequency: omega = 2π v = 2π × 20 = 40π rad/s . Maximum speed: v_{max = a omega = 0.02 × 40π approx 2.51 m/s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.