Practice question
Question
A telescope has an objective of focal length 160 cm and an eyepiece of focal length 8 cm . What is its magnifying power?
Explanation
Given:
A telescope has an objective of focal length 160 cm and an eyepiece of focal length 8 cm . What is its magnifying power?
These values define the system as per NCERT data.
Formula:
Magnifying power: m = f_o/f_e.
This is standard NCERT relation.
Substitution & Calculation:
f_o = 160 cm, f_e = 8 cm . m = 160/8 = 20 .
Result:
The computed value matches expected outcome and confirms correct choice as per NCERT.
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