Practice question

Given: A solid sphere of mass 5 kg and radius 0.2 m rotates at 10 rad/s . What is its angular momentum about its axis? Formula: I = 2/5 M R² = 2/5 × 5 × (0.2)² = 0.08 kg m². Substitution & Calculation: L = I omega = 0.08 × 10 = 0.8 kg m²/s . Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.