Practice question

Given: A particle in SHM has a = -16 x (in SI units). What is its period? These values define the system as per NCERT data. Formula: For SHM, a = -omega² x. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Given a = -16 x, so omega² = 16 Rightarrow omega = 4 rad/s . T = 2π/omega = 2π/4 = π/2 approx 1.57 s . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.