Practice question

Given: A 1350 kg car turns on a banked road ( θ = 25° ) with radius 50 m at the optimum speed to avoid friction. What is the speed? (Take g = 10 m/s², tan 25° approx 0.466 ) These values define the system as per NCERT data. Formula: Optimum speed: v_0 = sqrtrg tanθ (no friction contribution). This is standard NCERT relation. Substitution & Calculation: Substitute: r = 50 m, g = 10 m/s², tan 25° = 0.466 . v_0² = 50 × 10 × 0.466 = 500 × 0.466 = 233 . v_0 = sqrt233 approx 15.26 m/s . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.