Practice question
Question
The magnetic potential energy of a dipole with m = 0.3 A m² in a field B = 0.6 T at 45° is:
Explanation
Given:
The magnetic potential energy of a dipole with m = 0.3 A m² in a field B = 0.6 T at 45° is:
These values define the system as per NCERT data.
Formula:
U_m = -m B cosθ.
This is the standard NCERT relation for this phenomenon.
Substitution & Calculation:
Given: m = 0.3 A m², B = 0.6 T, θ = 45°, cos 45° = frac1sqrt2 approx 0.707 . Substitute: U_m = -0.3 × 0.6 × 0.707 approx -0.12726 J approx -0.13 J .
Result:
The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kgâ»Â¹ Kâ»Â¹, m/s², 10â»âµ are properly used as per NCERT.
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