Practice question

Given: In the reaction Fe₂O₃ + 3CO -> 2Fe + 3CO₂, how many grams of CO₂ are produced from 80 g of Fe₂O₃ with excess CO? (Atomic masses: Fe = 56, O = 16, C = 12) Formula: Molar mass of Fe₂O₃ = (2 × 56) + (3 × 16) = 160 g/mol. Substitution & Calculation: Moles of Fe₂O₃ = 80 / 160 = 0.5 mol. 1 mol Fe₂O₃ produces 3 mol CO₂. Moles of CO₂ = 0.5 × 3 = 1.5 mol. Mass = 1.5 × 44 = 66 g. Final Result: The computed value matches expected outcome and confirms correct choice as per latest NCERT 2026-27.