Practice question

Given: In a double-slit experiment, what is the distance of the second bright fringe from the ntral maximum if lambda = 500 nm, d = 0.2 mm, and D = 1.0 m ? These values define the system as per NCERT data. Formula: Distance x_n = n lambda D/d. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: For the second bright fringe, n = 2 . lambda = 5.0 × 10⁻⁷ m, d = 2.0 × 10⁻⁴ m, D = 1.0 m . x_2 = frac2 × 5.0 × 10⁻⁷ × 1.02.0 × 10⁻⁴= 5.0 × 10⁻³ m = 5.0 mm . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.