Practice question

Given: A gas has a solubility of 0.015 mol/L in water at a partial pressure of 3 bar at 298 K. What is the Henry's law constant ( K_H ) in bar? These values define the system as per NCERT data. Formula: Henry's law: p = K_H · solubility (in molarity). This is the standard NCERT relation for this phenomenon. Substitution & Calculation: K_H = fracpsolubility = 3/0.015 = 200 bar . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.