Practice question
Question
A force F = -5i + 2j N acts on a particle moving along d = 3i + 4j m . What is the work done?
Explanation
Given:
A force F = -5i + 2j N acts on a particle moving along d = 3i + 4j m . What is the work done?
These values define the system as per NCERT data.
Formula:
Work W = F · d.
This is standard NCERT relation.
Substitution & Calculation:
F = -5i + 2j, d = 3i + 4j . Scalar product: W = (-5 × 3) + (2 × 4) = -15 + 8 = -7 J .
Result:
The computed value matches expected outcome and confirms correct choice as per NCERT.
Discussion
Comments
Please log in to join the discussion.
Login to commentNo comments yet. Be the first to start the discussion.