Practice question
Question
A double convex lens of refractive index 1.55 has radii of curvature 30 cm and -30 cm . What is its focal length?
Explanation
Given:
A double convex lens of refractive index 1.55 has radii of curvature 30 cm and -30 cm . What is its focal length?
These values define the system as per NCERT data.
Formula:
Lens maker’s formula: 1/f = (n - 1) ( 1/R_1 - 1/R_2 ).
This is standard NCERT relation.
Substitution & Calculation:
n = 1.55, R_1 = 30 cm, R_2 = -30 cm . 1/f = (1.55 - 1) ( 1/30 - 1/-30 ) = 0.55 ( 1/30 + 1/30 ) = 0.55 × 2/30 = 1.1/30 . f = 30/1.1 approx 27.27 cm .
Result:
The computed value matches expected outcome and confirms correct choice as per NCERT.
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