Practice question

Given: A circular loop of radius 0.2 m with 10 turns carries 1.5 A . What is the magnetic field at its nter? ( μ_0 = 4 π × 10⁻⁷T m/A ) These values define the system as per NCERT data. Formula: Magnetic field B = μ_0 N I/2 R. This is standard NCERT relation. Substitution & Calculation: B = frac4 π × 10⁻⁷ × 10 × 1.52 × 0.2 = frac6 π × 10⁻⁶⁰.4 = 1.5 π × 10⁻⁵approx 4.71 × 10⁻⁵T . Result: The computed value matches expected outcome and confirms correct choice as per NCERT.