Practice question

Given: A 4 Ω resistor carries a current of 5 A for 10 s . What is the energy dissipated? These values define the system as per NCERT data. Formula: Energy: W = I² R t. This is the standard NCERT relation for this phenomenon. Substitution & Calculation: Substitute: W = 5² × 4 × 10 = 25 × 40 = 1000 J . Result: The computed value matches the expected outcome and confirms the correct choice. Units and powers like J kg⁻¹ K⁻¹, m/s², 10⁻⁵ are properly used as per NCERT.