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The Δ Hf for CO can be found from the second reaction: Δ Hf (CO) = Δ Hf (CO₂) + 283 = -393.5 + 283 = -110.5 kJ/mol.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Thermodynamic Terms - System Surroundings and Types of Systems
Δ H = [Δ Hf° (CO₂) + 2 × Δ Hf° (H₂)] - [Δ Hf° (C) + 2 × Δ Hf° (H₂O)] = [-393.5 + 0] - [0 + 2(-241.8)] = -393.5 + 483.6 = 90.1 kJ/mol.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Gibbs Energy and Gibbs Energy Change and Equilibrium
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