Calculate Δ H for the reaction C(s) + 2H₂(g) → CH₄(g) given: CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l), Δ H = -890.3 kJ/mol; C(
Reverse first: Δ H = 890.3 kJ. Second: Δ H = -393.5 kJ. Third (×2): Δ H = -571.6 kJ. Add: 890.3 - 393.5 - 571.6 = -74.8 kJ/mol.
Ref: NCERT Class 11 Chemistry > Chapter 5: Thermodynamics > Topic: Third Law of Thermodynamics and Applications