What is the force on a submarine window (0.08m2) at 300m depth in seawater (ρ\=1.03×103kg/m3), interior at atmospheric p
Gauge pressure: Pg = ρgh = 1.03×103×10×300 = 3.09×106Pa. F = PgA = 3.09×106×0.08 = 2.472×105N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.47 × 10⁵ N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.