Practice question
Question
What is the force on a submarine window (0.08m2) at 300m depth in seawater (ρ\=1.03×103kg/m3), interior at atmospheric pressure? (Take g\=10m/s2)
Explanation
Gauge pressure: Pg = ρgh = 1.03×103×10×300 = 3.09×106Pa. F = PgA = 3.09×106×0.08 = 2.472×105N. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.47 × 10⁵ N. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
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