A ball is projected at 30m/s at 53∘. What is the time to reach maximum height? (Take g\=10m/s2,sin53∘\=0.8)
At max height v=0. Using v²=u²-2gh from NCERT kinematics, h=u²/2g. With u=30 m/s and g=10 m/s², h=45.0 m. This matches option A (2 s). Other options do not satisfy v²=u²+2as with correct signs.
Ref: NCERT Class 11 Physics > Chapter 3: Motion in a Straight Line > Topic: Motion Parameters and Calculations