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Practice question

MCQ

Question

A ball is projected at 30m/s at 53∘. What is the time to reach maximum height? (Take g\=10m/s2,sin⁡53∘\=0.8)

Options

Choose one · Correct answer highlighted

Explanation

At max height v=0. Using v²=u²-2gh from NCERT kinematics, h=u²/2g. With u=30 m/s and g=10 m/s², h=45.0 m. This matches option A (2 s). Other options do not satisfy v²=u²+2as with correct signs.

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