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Practice question

MCQ

Question

A vehicle moving at 30m/s decelerates uniformly to rest in 100m. What is the time taken to stop?

Options

Choose one · Correct answer highlighted

Explanation

Use v2=v02+2ax to find a: 0=(30)2+2a(100)⇒0=900+200a⇒a=−4.5m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 6 s as the result, so option B is correct.

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