Practice question
Question
A particle accelerates uniformly from 6m/s to 18m/s in 3s. What is the distance covered?
Explanation
Find a=v−v0t=18−63=4m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 36 m as the result, so option B is correct.