Practice question
Question
A car moving at 27m/s decelerates uniformly to rest in 9s. What is the distance covered?
Explanation
Find a=v−v0t=0−279=−3m/s2. As per NCERT Chapter 3, equations v=u+at, s=ut+½at², v²=u²+2as describe uniformly accelerated motion. Applying correct signs and units gives 100 m as the result, so option A is correct.