Skip to content
Login Register

Practice question

MCQ

Question

A gas occupies 4.2L at 1.4atm and 47∘C. If the pressure is increased by 0.6atm and temperature decreased by 20∘C, what is the new volume?

Options

Choose one · Correct answer highlighted

Explanation

Given: V1 = 4.2L, P1 = 1.4atm, T1 = 47∘C = 320K, P2 = 1.4+0.6 = 2atm, T2 = 47−20 = 27∘C = 300K. P1V1T1 = P2V2T2. V2 = V1×P1P2×T2T1 = 4.2×1.42×300320 = 4.2×0.7×0.9375≈2.76L.

Discussion

Comments

0 comments

Share your thoughts. New comments appear after admin approval.

No comments yet. Be the first to start the discussion.

Related blogs

Guides and insights connected to this topic