Practice question
Question
A gas occupies 2.5L at 1.2atm and 37∘C. If the pressure is doubled and temperature increased by 50∘C, what is the new volume?
Explanation
Given: V1 = 2.5L, P1 = 1.2atm, T1 = 37∘C = 310K, P2 = 2.4atm, T2 = 37+50 = 87∘C = 360K. P1V1T1 = P2V2T2. V2 = V1×P1P2×T2T1 = 2.5×1.22.4×360310 = 2.5×0.5×1.1613≈1.45L.
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