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#uniform charge

3 public questions tagged with this topic.

Energy Stored in Capacitor and Energy Density

Why does the electric field due to an infinite charged sheet remain constant with distance from the sheet?

**Energy stored in capacitor** U = ½ C V² = ½ Q V = Q²/(2C) (J), C capacitance (F), V voltage (V), Q charge (C). For 4 μF charged to 250 V, U=0.5×4×10⁻⁶×62500=0.125 J. Energy resides in electric field, energy density u = ½ ε₀ E² (J/m³), E field between plates. Using Gauss’s law for an infinite charged sheet with surface charge density sigma , a Gaussian surface (e.g., a cylinder perpendicular to the sheet) shows that the electric field E is perpendicular to the sheet and constant. The flux through the cylinder's end caps is E · 2A , and the enclosed charge is

Ref: NCERT > Physics Book > Electrostatic Potential and Capacitance > Energy Stored in Capacitor and Energy Density

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Field Due to Special Charge Configurations

Why does the electric field due to a uniformly charged infinite plane sheet remain constant with distance from the sheet

**Field due to infinite plane and shells** illustrates symmetry power. Infinite plane's field remains constant because distant contributions balance, while spherical shell interior field cancels symmetrically, leading to E = 0 inside, E = kQ/r² outside. For an infinite plane sheet, symmetry and Gauss’s law show that the field depends only on surface charge density, not distance. The field lines are parallel and uniform, as contributions from all parts of the infinite sheet balance out distance effects. Substituting values gives Infinite extent, which matches expected magnitude for this electro

Ref: NCERT > Physics Book > Electric Charges and Fields > Field Due to Special Charge Configurations

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Electric Field and Electric Field Lines

Why does the electric field due to a uniformly charged infinite plane remain unaffected by the distance from the plane?

**Field intensity** at distance r follows inverse-square law E = (1/4π ε₀)·q/r². At midpoint between two charges, fields superpose vectorially; if charges opposite, fields add in same direction, enhancing magnitude to E = E₁ + E₂. The infinite extent of the plane ensures uniform field distribution, as contributions from all parts balance out distance effects. Gauss’s law confirms the field is sigma/2ε₀ , independent of distance due to symmetry. Substituting values gives Infinite extent, which matches expected magnitude for this electrostatic configuration, confirming Coulomb's and Gauss's prin

Ref: NCERT > Physics Book > Electric Charges and Fields > Electric Field and Electric Field Lines

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