The General Mathematics 4 category offers a collection of questions covering advanced arithmetic, algebra, geometry, and data interpretation. It helps students practice key concepts and improve problem‑solving skills.
Simply put, complete solution: write formula, plug data, do arithmetic. Final value matches d²y/dx² + (dy/dx)³ d²x/dy² = 0. Simple and accurate.
Ref: NCERT Mathematics Class XI and XII
Understanding this is easy: using formula we get point of inflexion at = 0. Calculation gives this directly, check steps: apply rule, substitute values, simplify to get point of inflexion at = 0.
Ref: NCERT Mathematics Class XI and XII
Recall the rule solving fully: apply relevant formula, put numbers, compute. Result comes as f is increasing in [1,∞). Easy verification shows it satisfies condition.
Ref: NCERT Mathematics Class XI and XII
The logic is straightforward: we verify all x ∈ (R−I) by full calculation: use standard identity, substitute, simplify step by step to reach all x ∈ (R−I).
Ref: NCERT Mathematics Class XI and XII
We can see that we verify Does not possess a maximum or minimum value by full calculation: use standard identity, substitute, simplify step by step to reach Does not possess a maximum or minimum value.
Ref: NCERT Mathematics Class XI and XII
The trick is we verify (A) - (I), (B) - (II), (C) - (III), (D) - (IV) by full calculation: use standard identity, substitute, simplify step by step to reach (A) - (I), (B) - (II), (C) - (III), (D)
Ref: NCERT Mathematics Class XI and XII
The logic is straightforward: we verify 2 by full calculation: use standard identity, substitute, simplify step by step to reach 2.
Ref: NCERT Mathematics Class XI and XII
From the definition, after simplifying, Jacob Bernoulli is left. The method is simple: formula → substitution → calculation → answer.
Ref: NCERT Mathematics Class XI and XII
Let's break it down: solving fully: apply relevant formula, put numbers, compute. Result comes as binomial distribution. Easy verification shows it satisfies condition.
Ref: NCERT Mathematics Class XI and XII
Understanding this is easy: we verify poisson distribution by full calculation: use standard identity, substitute, simplify step by step to reach poisson distribution.
Ref: NCERT Mathematics Class XI and XII
In easy words, we verify π/3 by full calculation: use standard identity, substitute, simplify step by step to reach π/3.
Ref: NCERT Mathematics Class XI and XII
The logic is straightforward: after simplifying, They are equal is left. The method is simple: formula → substitution → calculation → answer.
Ref: NCERT Mathematics Class XI and XII
