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E°cell = E°cathode - E°anode = -0.13 - (-0.14) = 0.01 V .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Corrosion and Applications of Electrochemistry
E°cell = E°cathode - E°anode = -0.13 - (-0.14) = 0.01 V .
Ref: NCERT Class 12 Chemistry > Chapter 2: Electrochemistry > Topic: Corrosion and Applications of Electrochemistry
HNO₃ (N: +5) is reduced to NO (N: +2), oxidizing Sn (0 to +4).
Ref: NCERT Class 11 Chemistry > Chapter 7: Redox Reactions > Topic: Types of Redox Reactions - Combination Decomposition Displacement
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