A uniform rod of mass 7kg and length 1.5m is pivoted at one end. What is its moment of inertia about the pivot?
For a rod pivoted at one end: I = 13ML2. M = 7kg, L = 1.5m. I = 13×7×(1.5)2 = 7×2.253 = 5.25kg m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 5.25 kg m². This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
