A uniform rod of mass 3kg and length 1.5m is pivoted at one end. What is its moment of inertia about the pivot?
For a rod pivoted at one end: I = 13ML2. M = 3kg, L = 1.5m. I = 13×3×(1.5)2 = 1×2.25 = 2.25kg m2. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2.25 kg m². This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCERT Class 11 Physics, Thermal Properties and Gravitation.
