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#oscillator

2 public questions tagged with this topic.

What happens to the frequency of a spring-mass system if the spring constant is quadrupled and the mass is halved?

**SHM representation** using sine or cosine equivalent with phase offset, ω relates to system parameters like mass and stiffness. Understanding ω and φ permits prediction of position at any time and comparison of two SHM via phase difference Δφ = φ₂ - φ₁. Frequency v = (1/2π) √((k/m)) . If k' = 4k and m' = (m/2) , then v' = (1/2π) √((4k/m/2)) = (1/2π) √((8k/m)) = √(8) · v = 2√(2) · v , doubling the original frequency by √(2) . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result

Ref: NCERT > Physics Book > Oscillations > Equations of SHM, Phase and Angular Frequency

A spring-mass system has \( m = 1.5 \, \text{kg}, k = 600 \, \text{N/m} \). What is its period?

**Spring-mass system** has period T = 2π√(m/k), frequency f = (1/2π)√(k/m), ω = √(k/m), where k spring constant (N/m) and m mass (kg). For parallel combination, k_eff = k₁ + k₂, series gives 1/k_eff = 1/k₁ + 1/k₂, affecting ω = √(k_eff/m) and T = 2π√(m/k_eff). Period: T = 2π √((m/k)) = 2π √((1.5/600)) = 2π √(0.0025) = 2π × 0.05 ≈ 0.314 s . Applying x = A cos(ωt + φ), v = -ωA sin(ωt + φ), a = -ω²x and E = ½kA² = ½mω²A², result 0.314 s follows, reflecting SHM dependence on amplitude A, ω and system parameters.

Ref: NCERT > Physics Book > Oscillations > Spring-Mass System and Combination of Springs