16 public questions tagged with this topic.
For Mg(OH)2 Mg²⁺ + 2OH- , Ksp = [Mg²⁺][OH-]² = 1.8 × 10⁻¹¹ , (1.0 × 10⁻⁴)[OH-]² = 1.8 × 10⁻¹¹ , [OH-]² = 1.8 × 10⁻⁷ , [OH-] = 1.34 × 10⁻⁴ , pOH = 3.87 , pH = 14 - 3.87 = 10.13 .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Relationship Between Kp Kc and Factors Affecting Equilibrium - Le Chatelier
For CaF₂ Ca²⁺ + 2F- , Ksp = [Ca²⁺][F-]² = 3.9 × 10⁻¹¹ . [F-] = 0.02 + 2[Ca²⁺] ≈ 0.02 , [Ca²⁺] (0.02)² = 3.9 × 10⁻¹¹ , [Ca²⁺] = 9.75 × 10⁻⁸ M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Relationship Between Kp Kc and Factors Affecting Equilibrium - Le Chatelier
For AgIO₃ Ag+ + IO₃- , Ksp = [Ag+][IO₃-] = 3.0 × 10⁻⁸ . [IO₃-] = 0.02 + [Ag+] ≈ 0.02 M , [Ag+] = (3.0 × 10⁻⁸/0.02) = 1.5 × 10⁻⁶ M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Homogeneous and Heterogeneous Equilibria and Applications of Equilibrium Constant
Ksp = [Ag+][Cl-] = 1.8 × 10⁻¹⁰ , [Cl-] ≈ 0.05 , [Ag+] = (1.8 × 10⁻¹⁰/0.05) = 3.6 × 10⁻⁹ M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Chemical Equilibrium - Law of Mass Action and Equilibrium Constant
For Ag₂CO₃ 2Ag+ + CO₃²⁻ , [Ag+] = 0.1 + 2S ≈ 0.1 M , [CO₃²⁻] = S = 2.0 × 10⁻⁶ . Ksp = [Ag+]²[CO₃²⁻] = (0.1)² (2.0 × 10⁻⁶) = 2.0 × 10⁻⁸ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
For Ag₂CrO₄ 2Ag+ + CrO₄²⁻ , [Ag+] = 2S = 2.6 × 10⁻⁴ , [CrO₄²⁻] = S = 1.3 × 10⁻⁴ . Ksp = (2.6 × 10⁻⁴)² (1.3 × 10⁻⁴) = 8.79 × 10⁻¹² .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
For PbI₂ Pb²⁺ + 2I- , [Pb²⁺] = 1.0 × 10⁻⁴ , [I-] = 0.05 + 2 × 1.0 × 10⁻⁴ ≈ 0.05 M . Ksp = [Pb²⁺][I-]² = (1.0 × 10⁻⁴) (0.05)² = 2.5 × 10⁻⁷ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
CaF₂ Ca²⁺ + 2F⁻ , Ksp = [Ca²⁺][F⁻]² = S (2S)² = 4S³ = 1.0 × 10⁻⁶ . Solving, S³ = 2.5 × 10⁻⁷ , S ≈ 6.3 × 10⁻³ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
For PbCl₂ Pb²⁺ + 2Cl- , Ksp = [Pb²⁺][Cl-]² = 1.7 × 10⁻⁵ . Let solubility = S , [Cl-] = 0.1 + 2S ≈ 0.1 , S (0.1)² = 1.7 × 10⁻⁵ , S = (1.7 × 10⁻⁵/0.01) = 1.7 × 10⁻³ M .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
For Ag₂SO₄ 2Ag+ + SO₄²⁻ , [Ag+] = 2 × 5.0 × 10⁻⁵ = 1.0 × 10⁻⁴ , [SO₄²⁻] = 0.1 + 5.0 × 10⁻⁵ ≈ 0.1 . Ksp = (1.0 × 10⁻⁴)² × 0.1 = 1.0 × 10⁻⁹ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
For BaSO₄ Ba²⁺ + SO₄²⁻ , [Ba²⁺] = 2.0 × 10⁻⁹ , [SO₄²⁻] ≈ 0.05 , Ksp = (2.0 × 10⁻⁹) × 0.05 = 1.0 × 10⁻¹⁰ .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
For MX₂ M²⁺ + 2X⁻ , [M²⁺] = S , [X⁻] = 2S , so Ksp = S (2S)² = 4S³ . Thus, [X⁻] = 2[M²⁺] .
Ref: NCERT Class 11 Chemistry > Chapter 6: Equilibrium > Topic: Buffer Solutions and Solubility Product and Common Ion Effect
