We use cookies to improve your experience and understand how Examtube is used. You can accept analytics cookies or continue with essential cookies only.
Privacy policy3 public questions tagged with this topic.
Pav = FA, F = mg = 60×10 = 600N. Total area A = 2×25×10−4 = 5.0×10−3m2. Pav = 6005.0×10−3 = 1.2×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.2 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Pav = FA, F = mg = 65×10 = 650N. Total area A = 2×20×10−4 = 4.0×10−3m2. Pav = 6504.0×10−3 = 1.625×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 1.625 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option C is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Pav = FA, F = mg = 60×10 = 600N. Total area A = 2×15×10−4 = 3×10−3m2. Pav = 6003×10−3 = 2×105Pa. As per NCERT, applying relevant law/formula with correct units and sign convention leads to 2 × 10⁵ Pa. This satisfies dimensional consistency and physical conditions given, so option B is scientifically correct.
Ref: NCBI Bookshelf, Ideal Gas Law: P1V1/T1 = P2V2/T2.
Add our app to your home screen for a better experience.
This page is supported by advertisements. An ad blocker is stopping those ads from loading, so we cannot show the rest of the page yet. Pause the blocker for this site, then continue. We will check again automatically.
You can keep using this site after advertisements are allowed to load.
