A solution contains 30 g of a solute in 120 g of water. If the mass percentage of the solute is increased to 25% by evap
Initial mass % = (30/30 + 120) × 100 = 20% . New mass % = 25% = (30/30 + w) × 100 . 0.25 (30 + w) = 30 , 30 + w = 120 , w = 90 g .
Ref: NCERT Class 12 Chemistry > Chapter 1: Solutions > Topic: Abnormal Molar Masses and van't Hoff Factor
