We use cookies to improve your experience and understand how Examtube is used. You can accept analytics cookies or continue with essential cookies only.
Privacy policy5 public questions tagged with this topic.
Each ethane-1,2-diamine (en) is bidentate (2 donor atoms), and each H₂O is unidentate. In [Ni(en)2(H₂O)2]2+, 2 en (4 atoms) + 2 H₂O = 6.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Werner's Theory and Definitions - Ligands Coordination Number
In [Cu(en)2]2+, each ethane-1,2-diamine (en) is bidentate, contributing 2 donor atoms. Total = 2 × 2 = 4.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Werner's Theory and Definitions - Ligands Coordination Number
In [Co(NH₃)4(en)]3+, 4 NH₃ provide 4 N atoms, and 1 en (bidentate) provides 2 N atoms. Total = 4 + 2 = 6.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Nomenclature of Coordination Compounds
[Co(en)3]3+ contains 3 ethane-1,2-diamine (en) ligands, a bidentate ligand denoted as H₂NCH₂CH₂NH₂.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Colour and Magnetic Properties and Stability and Importance
[Ni(en)2]2+ (Ni₂+, d8) with 2 bidentate en (4 donor atoms) is square planar, using dsp2 hybridization.
Ref: NCERT Class 12 Chemistry > Chapter 5: Coordination Compounds > Topic: Bonding - Valence Bond Theory and Hybridisation
Add our app to your home screen for a better experience.
This page is supported by advertisements. An ad blocker is stopping those ads from loading, so we cannot show the rest of the page yet. Pause the blocker for this site, then continue. We will check again automatically.
You can keep using this site after advertisements are allowed to load.
