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#electronic transition

2 public questions tagged with this topic.

What kind of transition is allowed in UV for benzene ring?

Benzene aromatic ring archetype possesses planar conjugated system with six π electrons delocalized over three formal double bonds, satisfying Hückel rule. Ultraviolet absorption involves promotion of an electron from filled bonding π orbital to vacant antibonding π* orbital. This π→π* transition is symmetrically allowed, intense, with molar extinction about 200 to 10,000 M-1 cm-1 and characteristic vibronic fine structure near 255 nm known as primary and secondary benzenoid bands. σ→σ* requires far vacuum UV, n-related transitions absent due to lack of heteroatom lone pairs, explaining phenyl

Ref: NCERT Biology Class XII Principles on Klenow fill-in labeling, Lehninger Chapter 9 DNA cloning techniques, and Molecular Cloning by Sambrook Chapter 10 documenting end-labeling of cohesive termini.

Which transition results in fluorescence emission?

In Jablonski representation, absorption excites an electron from ground S0 to vibrationally excited levels of S1. Rapid internal conversion and vibrational relaxation bring the molecule to the lowest S1 level within picoseconds, following Kasha rule. Fluorescence is the radiative return from this relaxed S1 state back to various vibrational levels of S0, emitting a photon of lower energy. S0 to S1 represents absorption, S1 to T1 denotes intersystem crossing, and T1 to S0 yields delayed phosphorescence. Only S1 to S0 corresponds to prompt fluorescence.

Ref: NCERT Biology Class XII Principles on Klenow fill-in labeling, Lehninger Chapter 9 DNA cloning techniques, and Molecular Cloning by Sambrook Chapter 10 documenting end-labeling of cohesive termini.